page 98
Provenance
- transcript transcript
- 2026-09-29T23:41:07+00:00 machine-generated
- normalization normalization
- 2026-10-02T18:15:40+00:00 machine-generated
Full TPME chain
[
{
"_schema": {
"id": "https://doi.org/10.5281/zenodo.21287085",
"name": "AI4LAM TPME",
"version": "1.0"
},
"conventions": [
"diplomatic",
"https://github.com/selic/bookolot/blob/main/docs/transcription-guide.md"
],
"features": {
"bbox_space": "deskewed page, see deskew step",
"line_bbox": true,
"line_confidence": true,
"word_bbox": false
},
"file_format": "ALTO 4",
"human_review_level": "machine-generated",
"media_id": "http://www.moldavica.bnrm.md/biblielmo?l=ro\u0026a=d\u0026c=carti\u0026d=JD3364",
"media_title": "Priblijonnoe iscislenie",
"modification_date": "2026-09-29T23:41:07+00:00",
"originating_media_file": "98.tif",
"processing": [
{
"application_name": "kraken blla",
"application_parameters": {
"device": "cuda",
"model": "blla.mlmodel (встроенная)"
},
"application_provider": "Benjamin Kiessling",
"application_repo": "https://github.com/mittagessen/kraken",
"application_type": "line segmentation",
"application_version": "7.1.1"
},
{
"application_name": "kraken",
"application_parameters": {
"device": "cuda"
},
"application_provider": "Benjamin Kiessling",
"application_repo": "https://github.com/mittagessen/kraken",
"application_type": "OCR",
"application_version": "7.1.1",
"inference_model": "ppocrv6_medium (sha256:15313b51ace64cbf)"
}
],
"provider": "Bookolot",
"transcript_checksum": "sha256:dff317d7e90be164ce2b85c5086a968367c90f6804aa92d0c9fd1b9deee62e78",
"transcript_id": "bookolot:JD3364:98:ocr-v1",
"transcript_language": [
"ru-petr1708"
],
"type": "transcript"
},
{
"_schema": {
"id": "https://doi.org/10.5281/zenodo.21287085",
"name": "AI4LAM TPME",
"version": "1.0"
},
"characteristics_note": "For reading and search only; quote the parent transcript.",
"human_review_level": "machine-generated",
"media_id": "http://www.moldavica.bnrm.md/biblielmo?l=ro\u0026a=d\u0026c=carti\u0026d=JD3364",
"media_title": "Priblijonnoe iscislenie",
"modification_date": "2026-10-02T18:15:40+00:00",
"originating_media_file": "98.tif",
"parent_transcript_id": "bookolot:JD3364:98:ocr-v1",
"processing": [
{
"application_name": "bookolot.rag.normalize",
"application_parameters": {
"normalizer_version": 3,
"script": "ru_prereform"
},
"application_provider": "Bookolot",
"application_repo": "https://github.com/selic/bookolot",
"application_type": "spelling normalization",
"application_version": "fb8b81d-dirty"
}
],
"provider": "Bookolot",
"transcript_checksum": "sha256:57edbcb6c8f3df3e8a7419c24ce8a6a260a7560e1588553f5169483655fca7a7",
"transcript_id": "bookolot:JD3364:98:modern-v3",
"transcript_language": [
"ru-t-ru-petr1708"
],
"type": "normalization"
}
]
This scan cannot be decoded: the TIFF in the archive is damaged. The text is recognised, the image is not available.
confident worth a look check the scan Open the full scan
Text as printedmodern spellingboth
as printed − 3 + modern spelling − 5 +
- 0 – 95 – 0.81
- 1 г надо вычислить приближенно съ избыткомъ; поэтому вмѣсто 0.99
- 2 и v надо подставить такія изъ возможныхъ для нихъ значе- 0.97
- 3 нія, при которыхъ г будетъ имѣть найбольшее значеніе. Надо 1.00
- 4 приять – =; тогда 0.84
- 5 37,143 0.92
- 6 2,13 1.00
- 7 2 0.98
- 8 0,002+0,0 1.00
- 9 ли 0.88
- 10 37.143 0.91
- 11 r– 17,5(0,002-+0,175) —17,5.0,177— 3,1 0.91
- 12 Итакъ предѣломъ неизбљжной погрѣшности въ ъ будетъ 3,1. 0.96
- 13 Вычисляемъ нисшій пределъ съ точностью до—10,1. Чи¬ 0.95
- 14 слителя надо вычислить съ точи. до10,01. 0.96
- 15 37,1420 1.00
- 16 2 4173 0.95
- 17 111 4260 0.95
- 18 25 9994 0.98
- 19 3714 0.99
- 20 1484 1.00
- 21 74 0.97
- 22 137,9526 0.99
- 23 137,96 2,140 0.95
- 24 128 40 64,4 0.95
- 25 9 56 1.00
- 26 8 56 1.00
- 27 100 1.00
- 28 85 0.94
- 29 15 1.00
- 30 Итакъ нисшій предѣлъ равенъ 64,3+0,26; слѣд. 0.94
- 31 2–64,3+0,2σ+,1–64+,, —64+4ω 0.80
- 32 Здѣсь 3,1 предѣлъ неизбѣжной погрѣшности, 0,2 предѣлъ 0.97
- 33 погрѣшности вычисленія, О,3 погрѣшность укорачиванья и 0,4 0.97
- 34 погрѣшность, произшедшая отъ упрощенія предела погрѣшности. 0.97
- 35 Примъчаяіе. Число, вычисленное съ найбольшей точностью, 0.98
- 36 не всегда слѣдуетъ приводить къ каноническому виду, потому 0.99
- 37 что это приведеніе часто очень значительно увеличиваетъ пре- 0.99
- 38 дѣлъ погрѣшности. 0.98
- 39 м 0.44