pagina 79

79 / 102 rusă, până în 1918 încredere 0.90 neverificat de om

Proveniență

transcript transcript: 2026-09-29T23:31:45+00:00 machine-generated
normalization normalization: 2026-10-02T18:15:39+00:00 machine-generated

Lanțul TPME complet

[
  {
    "_schema": {
      "id": "https://doi.org/10.5281/zenodo.21287085",
      "name": "AI4LAM TPME",
      "version": "1.0"
    },
    "conventions": [
      "diplomatic",
      "https://github.com/selic/bookolot/blob/main/docs/transcription-guide.md"
    ],
    "features": {
      "bbox_space": "deskewed page, see deskew step",
      "line_bbox": true,
      "line_confidence": true,
      "word_bbox": false
    },
    "file_format": "ALTO 4",
    "human_review_level": "machine-generated",
    "media_id": "http://www.moldavica.bnrm.md/biblielmo?l=ro\u0026a=d\u0026c=carti\u0026d=JD3364",
    "media_title": "Priblijonnoe iscislenie",
    "modification_date": "2026-09-29T23:31:45+00:00",
    "originating_media_file": "79.tif",
    "processing": [
      {
        "application_name": "kraken blla",
        "application_parameters": {
          "device": "cuda",
          "model": "blla.mlmodel (встроенная)"
        },
        "application_provider": "Benjamin Kiessling",
        "application_repo": "https://github.com/mittagessen/kraken",
        "application_type": "line segmentation",
        "application_version": "7.1.1"
      },
      {
        "application_name": "kraken",
        "application_parameters": {
          "device": "cuda"
        },
        "application_provider": "Benjamin Kiessling",
        "application_repo": "https://github.com/mittagessen/kraken",
        "application_type": "OCR",
        "application_version": "7.1.1",
        "inference_model": "ppocrv6_medium (sha256:15313b51ace64cbf)"
      }
    ],
    "provider": "Bookolot",
    "transcript_checksum": "sha256:f7049028eac7ae95bfe356aee497766f8d700b609e574027eb9f5833984073f0",
    "transcript_id": "bookolot:JD3364:79:ocr-v1",
    "transcript_language": [
      "ru-petr1708"
    ],
    "type": "transcript"
  },
  {
    "_schema": {
      "id": "https://doi.org/10.5281/zenodo.21287085",
      "name": "AI4LAM TPME",
      "version": "1.0"
    },
    "characteristics_note": "For reading and search only; quote the parent transcript.",
    "human_review_level": "machine-generated",
    "media_id": "http://www.moldavica.bnrm.md/biblielmo?l=ro\u0026a=d\u0026c=carti\u0026d=JD3364",
    "media_title": "Priblijonnoe iscislenie",
    "modification_date": "2026-10-02T18:15:39+00:00",
    "originating_media_file": "79.tif",
    "parent_transcript_id": "bookolot:JD3364:79:ocr-v1",
    "processing": [
      {
        "application_name": "bookolot.rag.normalize",
        "application_parameters": {
          "normalizer_version": 3,
          "script": "ru_prereform"
        },
        "application_provider": "Bookolot",
        "application_repo": "https://github.com/selic/bookolot",
        "application_type": "spelling normalization",
        "application_version": "fb8b81d-dirty"
      }
    ],
    "provider": "Bookolot",
    "transcript_checksum": "sha256:68666e54dc94a55ac710a0eff4da939077d2e576618ac57d65ae7e0a24faf1b0",
    "transcript_id": "bookolot:JD3364:79:modern-v3",
    "transcript_language": [
      "ru-t-ru-petr1708"
    ],
    "type": "normalization"
  }
]

sigur merită o privire verifică scanul Deschide scanul întreg

Text cum e tipărit ortografie modernă ambele

cum e tipărit − 5 + ortografie modernă − 2 +

0 1 0.94
1 1I 0.55
2 1 0.26
3 IV 0.98
4 VII 0.77
5 VIII 0.98
6 /3(a –b) 2+ ab] Yc 2 – ½ (a –b 0.75
7 тическихъ дѣйств. 0.96
8 a- 0.76
9 (a –b)² 0.81
10 /3(a -b) 0.75
11 /2(a -b) 0.85
12 ab 1.00
13 2 0.54
14 Єдивицы 0.87
15 нӑвысш. Степень точности. 0.91
16 разяд 0.64
17 1 1.00
18 10 1.00
19 10 1.00
20 10 1.00
21 10 1.00
22 100 1.00
23 (a-b)+-2b=p 10 0.80
24 c 21/2 (a-b) 2 =q 100 0.82
25 ra 0.61
26 76 0.95
27 Сноитческа табца. 0.74
28 V= 0.72
29 Формулы арнеже¬ 0.95
30 x v=pVq 0.65
31 10 1.00
32 +0,0000001 0.98
33 +0,00001 1.00
34 +0,0001 0.98
35 —0,001 0.95
36 +0,0001 1.00
37 +0,001 0.98
38 +0,0002 0.98
39 +0,002 0.98
40 +0,0002 1.00
41 +0,1 0.91
42 Результаты арне 0.95
43 метическихъ дѣй- 0.95
44 cri. 0.76
45 10,378143 0.98
46 3,010248 1.00
47 21,014856 1.00
48 7,3678950 1.00
49 54,28588 1.00
50 18,0953 1.00
51 27,143 1.00
52 31,2407 1.00
53 441,624 1.00
54 49,3360 1.00
55 414,481 1.00
56 20, 3588 0.98
57 1004,4 1.00
58 Анализъ вычисленія. Надо V вычислить съ точн. до—10,5, а для 0.96
59 этого надо (§ 15) предварительно вычислить V съ точн. д0—+0,1 0.96
60 Чтобы вычслить р съ точн. до +0,1, надо по правл 0.93
61 Ухтреда подписать единицы числа р подъ тысячными, а десяте 0.98
62 подъ десятитысячными долями числа V; поэтому Vд надо вы 0.95
63 чисить съ точн. до +0,0002. Съ такою же точностью надо вы 0.97
64 a 0.95