page 102
Provenance
- transcript transcript
- 2026-09-29T23:43:13+00:00 machine-generated
- normalization normalization
- 2026-10-02T18:15:40+00:00 machine-generated
Full TPME chain
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Text as printedmodern spellingboth
as printed − 2 + modern spelling − 1 +
- 0 –99 - 0.77
- 1 75. Приводимъ здѣсь примѣры на вычисленіе посредствомъ 0.99
- 2 логариемовъ, съ целью показать, какъ опредѣляется погрѣш¬ 0.95
- 3 ность въ результатв вычисленія, зависящая отъ неточностп 0.98
- 4 логариомовъ. Замѣтимъ, что, вычисляя алгебранческую формулу 0.98
- 5 посредствомъ логариемовъ, мы не можемъ предъявдять требо- 0.98
- 6 ванія вычпслнть искомую величину съ заранђе заданной точ¬ 0.96
- 7 ностью, а можемъ предъявить требованіе вычислить ее съ най¬ 0.98
- 8 болышею точностью, допускаемой неточностью тѣхъ или другихъ 0.99
- 9 логариомическихъ таблицъ. 0.97
- 10 Вычислить съ наӥбольшей точностью. 0.98
- 11 U=3 π ³, = 537,41863 0.82
- 12 logr=2,730313-+ 0.82
- 13 3logr=8,190939-+-3κ 0.78
- 14 π=0,497150-+-0,5 0.83
- 15 log 4 =0,602060 - 1-0,50 0.87
- 16 9,290149-+4 0.84
- 17 log 3 =0,477 121-+0,55 0.89
- 18 log U=8,813028-+-4,5+ 0.83
- 19 U= 650171000—+ 7000, 0.90
- 20 Вычислить съ найбольшей точностью катетъ с и углы 0.99
- 21 В и С прямоугольнаго треугольника, въ которомъ даны гиппо- 0.99
- 22 тенуза а и катетъ . 0.96
- 23 a=43,7842 0.89
- 24 b=27,4038 0.95
- 25 c=V(a+b)(a -b) sin B= 0.89
- 26 log(a –b) =1 214335-+» 0.82
- 27 log(a +b) =1,852407-+-0,5v 0.85
- 28 3,066742-+-1,53 0.87
- 29 logc= 1,533371-+-0,87 0.92
- 30 c== 34, 1484-1-0,00026 0.88
- 31 logb = 1,437811-+ε 0.87
- 32 loga= 1,641317-+0,56 0.94
- 33 logsin A= 9,796494-+1,5v 0.92
- 34 A= 38°44'50"+-2"ω 0.81
- 35 B= 41015'101-2"ω 0.84
- 36 a 0.98
- 37 a=43,7842 0.89
- 38 b= 27.4038 0.91
- 39 a – b = 16,3804 0.85
- 40 +=71,1880 0.92